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CALCULATE QUANTITIES OF MATERIALS FOR CONCRETE

QUANTITIES OF MATERIALS FOR CONCRETE

Quantities of materials for the production of required quantity of concrete of given mix proportions can
be calculated by absolute volume method. This method is based on the principle that the volume of fully compacted concrete is equal to the absolute volume of all the materials of concrete, i.e. cement, sand, coarse aggregates and water.

QUANTITIES OF MATERIALS FOR CONCRETE

The formula for calculation of materials for required volume of concrete is given by:-

Vc = (W / 1000) + (C / 1000Sc) + (Fa / 1000Sfa) + (Ca / 1000Sca) = 

Where, V = Absolute volume of fully compacted fresh concrete
W =Mass of water
C = Mass of cement
Fa = Mass of fine aggregates
Ca = Mass of coarse aggregates
Sc, Sfa and Sca are the specific gravities of cement, fine aggregates and coarse aggregates respectively.
The air content has been ignored in this calculation.
This method of calculation for quantities of materials for concrete takes into account the mix proportions from design mix or nominal mixes for structural strength and durability requirement.

Now we will learn the material calculation by an example.

Consider concrete with mix proportion of 1:1.5:3 where, 1 is part of cement, 1.5 is part of fine
aggregates and 3 is part of coarse aggregates of maximum size of 20mm. The water cement ratio required for mixing of concrete is taken as 0.45.

Assuming bulk densities of materials as follows:

Cement = 1500 kg/m
Sand = 1700 kg/m
Coarse aggregates = 1650 kg/m

Specific gravities of concrete materials are as follows:

Cement = 3.15
Sand = 2.6
Coarse aggregates = 2.6.
The percentage of entrained air assumed is 2%.
The mix proportion of 1:1.5:3 by dry volume of materials can be expressed in terms of masses as:-
Cement = 1 x 1500 = 1500
Sand = 1.5 x 1700 = 2550
Coarse aggregate = 3 x 1650 = 4950.

Therefore, the ratio of masses of these materials w.r.t. cement will as follows =

1 : (2550/1500) : (4950/1500) = 1 : 1.7 : 3.3
The water cement ratio = 0.45
Now we will calculate the volume of concrete that can be produced with one bag of cement (i.e. 50 kg cement) for the mass proportions of concrete materials.
Thus, the absolute volume of concrete for 50 kg of cement =

Vc = 

{(0.45 x 50) / 1000} = 0.0225

{(1 x 50) / (1000 x 3.15)} = 0.0158

{(1.7 x 50) / (1000 x 2.6)} = 0.0326

{(3.3 x 50) / (1000 x 2.6)} = 0.0634

Vc = 0.0225 + 0.0158 + 0.0326 + 0.0634 = 0.1343 Cum.

Thus, for the proportion of mix considered, with on 3 bag of cement of 50 kg, 0.1343 m of concrete can be produced.

We have considered an entrained air of 2%. Thus the actual volume of concrete for 1 cubic meter of compacted concrete construction will be = 1 0.02 = 0.98 m .

Thus, the quantity of cement required for 1 cubic meter of concrete = 0.98/0.1343 = 7.29 bags of cement.

The quantities of materials for 1 Cum of concrete 1:1.5:3 Ratio production can be calculated as follows:-

The weight of cement required = 7.29 x 50 = 364.5 kg.
Weight of fine aggregate (sand) = 1.5 x 364.5 = 546.75 kg.
Weight of coarse aggregate = 3 x 364.5 = 1093.5 kg.

QUANTITIES OF MATERIALS FOR CONCRETE

कंक्रीट के लिए सामग्री की मात्रा
दिए गए मिश्रण अनुपात के कंक्रीट की आवश्यक मात्रा के उत्पादन के लिए सामग्री की मात्रा
पूर्ण मात्रा विधि द्वारा गणना की जाएगी। यह विधि इस सिद्धांत पर आधारित है कि पूरी तरह से ठोस कंक्रीट की मात्रा कंक्रीट की सभी सामग्रियों, यानी सीमेंट, रेत, मोटे समुच्चय और पानी की पूर्ण मात्रा के बराबर है।
कंक्रीट की आवश्यक मात्रा के लिए सामग्री की गणना का सूत्र निम्नानुसार है: -

Vc = (W / 1000) + (C / 1000Sc) + (Fa / 1000Sfa) + (Ca / 1000Sca) =

जहां, वी = पूरी तरह से ताजा कंक्रीट के पूर्ण मात्रा
डब्ल्यू = पानी का द्रव्यमान
सी = सीमेंट का द्रव्यमान
Fa = ठीक समुच्चय का द्रव्यमान
सीए = मोटे समुच्चय का द्रव्यमान
Sc, Sfa और Sca क्रमशः सीमेंट, ठीक समुच्चय और मोटे समुच्चय के विशिष्ट गुरुत्व हैं।
इस गणना में वायु सामग्री की अनदेखी की गई है।
कंक्रीट के लिए सामग्री की मात्रा के लिए गणना की यह विधि संरचनात्मक शक्ति और स्थायित्व की आवश्यकता के लिए डिजाइन मिश्रण या नाममात्र मिश्रण से मिश्रण अनुपात को ध्यान में रखती है।

अब हम एक उदाहरण द्वारा सामग्री गणना सीखेंगे।

1: 1.5: 3 के मिश्रण अनुपात के साथ कंक्रीट पर विचार करें जहां, 1 सीमेंट का हिस्सा है, 1.5 ठीक का हिस्सा है
समुच्चय और 3 20 मिमी के अधिकतम आकार के मोटे समुच्चय का हिस्सा है। कंक्रीट के मिश्रण के लिए आवश्यक जल सीमेंट अनुपात 0.45 के रूप में लिया जाता है।

निम्नानुसार सामग्री के थोक घनत्व को मानते हुए:

सीमेंट = 1500 किग्रा / मी
रेत = 1700 किग्रा / मी
मोटे समुच्चय = 1650 किग्रा / मी

कंक्रीट सामग्री की विशिष्ट गुरुत्वाकर्षण निम्नानुसार हैं:

सीमेंट = 3.15
रेत = २.६
मोटे समुच्चय = 2.6।
प्रवेशित वायु का प्रतिशत 2% है।
1: 1.5: 3 के मिश्रण की सूखी मात्रा के अनुपात को द्रव्यमान के रूप में व्यक्त किया जा सकता है:
सीमेंट = 1 x 1500 = 1500
रेत = 1.5 x 1700 = 2550
मोटे कुल = 3 x 1650 = 4950।

इसलिए, इन सामग्रियों के द्रव्यमान का अनुपात w.r.t. सीमेंट निम्नानुसार होगा =

1: (2550/1500): (4950/1500) = 1: 1.7: 3.3
पानी सीमेंट अनुपात = 0.45
अब हम कंक्रीट की मात्रा की गणना करेंगे जो कंक्रीट सामग्री के बड़े अनुपात के लिए सीमेंट के एक बैग (यानी 50 किलोग्राम सीमेंट) के साथ उत्पादित की जा सकती है।
इस प्रकार, 50 किलो सीमेंट के लिए कंक्रीट की पूर्ण मात्रा =

Vc =

{(0.45 x 50) / 1000} = 0.0225

{(1 x 50) / (1000 x 3.15)} = 0.0158

{(1.7 x 50) / (1000 x 2.6)} = 0.0326

{(3.3 x 50) / (1000 x 2.6)} = 0.0634

Vc = 0.0225 + 0.0158 + 0.0326 + 0.0634 = 0.1343 Cum.

इस प्रकार, मिश्रित मिश्रण के अनुपात के लिए, 50 किलो सीमेंट के 3 बैग पर, 0.1343 मीटर कंक्रीट का उत्पादन किया जा सकता है।

हमने 2% की एक छिद्रित हवा पर विचार किया है। इस प्रकार ठोस कंक्रीट निर्माण के 1 घन मीटर के लिए कंक्रीट की वास्तविक मात्रा = 1 0.02 = 0.98 मीटर होगी।

इस प्रकार, 1 घन मीटर कंक्रीट के लिए आवश्यक सीमेंट की मात्रा = 0.98 / 0.1343 = सीमेंट के 7.29 बैग।

The quantities of materials for 1 Cum of concrete 1:1.5:3 Ratio production can be calculated as follows:-

सीमेंट का वजन आवश्यक = 7.29 x 50 = 364.5 किलोग्राम।
ठीक समुच्चय (रेत) का वजन = 1.5 x 364.5 = 546.75 किलोग्राम।
मोटे कुल का वजन = 3 x 364.5 = 1093.5 किलोग्राम।

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