Find Out dry Materials Required for 1 cum. Brick Masonry in Cement Sand mortar 1:5 Ratio.

Dry Materials Required for 1 cum. Brick Masonry in Cement Sand  mortar 1:5 Ratio.

Solution:-

Ratio = 1:5 (Cement, Sand)
Sum = 1+5 = 6
Total Dry Mortar for 1 cum Brick Masonry = 0.30733 Cum

Therefor, the Following Materials are Required:-

Cement = 1 x 0.30733 x 28.8 / 6 = 1.47 Bags
Sand     = 5 x 0.30733 / 6 = 0.2561 cum.

No. of Bricks Required for 1 cum. Brick Masonry = 500 no's.

Materials Required for 1 cum. Brick Masonry in 1:5 Ratio.

Cement =  1.474 Bags = 73.70 Kg
Sand     = 0.2561 cum. = 9.043 Cft

Note: 500 Bricks are Required for 1 cum.Brick Masonry.

Volume = 1 Cum.

Taking standard Mortar Thickness = 10mm

Cement –Sand Ratio = 1:5 = 1 + 5 = 6 Sum of Ratio.

We know that, Size of a Modular Brick = 190mm x 90mm x90mm

Volume of 1 Brick with Mortar = 200mm x 100mm x 100mm

= 0.2 x 0.1 x 0.1 m = 0.002 Cum

Therefore,

Number of Bricks in 1 Cum = 1/ 0.002 = 500 nos.

Volume of 1 Brick = 0.19 x 0.09 x 0.09 = 0.001539 Cum

Volume covered by 500 number of Bricks = 500 x 0.001539 = 0.7695 Cum

Volume of Mortar =1- 0.7695 = 0.2305 Cum { This is wet mortar }

For Dry Mortar, add 1/3 of the Wet Mortar = {( 1/3 ) x 0.2305} + 0.2305 = 0.30733 Cum

Now calculating the quantities of cement and sand in the 1:5 ratio,

CEMENT = {1/( 1+5) } x 0.30733 = 0.0512 Cum

= 0.0512 x 28.8 =1.474 Bags = 73.70 Kg {1 Cement Bag = 50 Kg }

SAND = {5/(1+5)} x 0.30733 = 0.2561 Cum

= 0.2561 x 35.314 {1 Cum = 35.314 Cft } = 9.043 Cft